"from, pH + pOH = 14\\\\\n\\begin{aligned}\n\\\\\npH &= 14 - pOH\\\\\npH &= 14 - 6.43\\\\\npH &= 7.57\n\n\\end{aligned}"
"\\begin{aligned}\n\n\\textsf{from, }pH &= -log[H_3O^+]\\\\\n\\\\\n7.57 &= -log[H_3O^+]\\\\\n-7.57 &= log[H_3O^+]\\\\\n10^{-7.57} &= [H_3O^+]\\\\\n[H_3O^+] &= 2.69 \u00d7 10^{-8}M\n\n\\end{aligned}"
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