Question #140747
Solve for the hydronium ion concentration of a solution with a pOH of 6.43
1
Expert's answer
2020-10-29T05:39:42-0400

from,pH+pOH=14pH=14pOHpH=146.43pH=7.57from, pH + pOH = 14\\ \begin{aligned} \\ pH &= 14 - pOH\\ pH &= 14 - 6.43\\ pH &= 7.57 \end{aligned}



from, pH=log[H3O+]7.57=log[H3O+]7.57=log[H3O+]107.57=[H3O+][H3O+]=2.69×108M\begin{aligned} \textsf{from, }pH &= -log[H_3O^+]\\ \\ 7.57 &= -log[H_3O^+]\\ -7.57 &= log[H_3O^+]\\ 10^{-7.57} &= [H_3O^+]\\ [H_3O^+] &= 2.69 × 10^{-8}M \end{aligned}


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