from,pH+pOH=14pH=14−pOHpH=14−6.43pH=7.57from, pH + pOH = 14\\ \begin{aligned} \\ pH &= 14 - pOH\\ pH &= 14 - 6.43\\ pH &= 7.57 \end{aligned}from,pH+pOH=14pHpHpH=14−pOH=14−6.43=7.57
from, pH=−log[H3O+]7.57=−log[H3O+]−7.57=log[H3O+]10−7.57=[H3O+][H3O+]=2.69×10−8M\begin{aligned} \textsf{from, }pH &= -log[H_3O^+]\\ \\ 7.57 &= -log[H_3O^+]\\ -7.57 &= log[H_3O^+]\\ 10^{-7.57} &= [H_3O^+]\\ [H_3O^+] &= 2.69 × 10^{-8}M \end{aligned}from, pH7.57−7.5710−7.57[H3O+]=−log[H3O+]=−log[H3O+]=log[H3O+]=[H3O+]=2.69×10−8M
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