Solution.
3.9×10−8=x2(0.0393−x)3.9\times 10^{-8} = \frac{x^2}{(0.0393-x)}3.9×10−8=(0.0393−x)x2
x=3.91×10−5x = 3.91 \times 10^{-5}x=3.91×10−5
pH=−lg[H+]=4.41pH = -lg[H^+] = 4.41pH=−lg[H+]=4.41
Answer:
4.41
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