Answer to Question #14027 in Inorganic Chemistry for shashi kumar

Question

a reaction of second order with respect to a reactant.how is the rate of reaction affected if the concentration of the reactants is reduced half? what is the unit of rate constant of such reaction?

Answer 1

Look in your text book for the 2^nd order chemical reaction (shown below) and plug n chug fake numbers into [A], the concentration, t (time in seconds), and
A₀ and see what happens to k (the rate of the reaction) when you double and reduce A by half.

1/[A] = kt + 1/A₀

Rate = k[A]^2

mol/sec = k(mol/L)^2 = k(mol²/L²)

k = L²/mol-sec