Question

For a molecule A, the plot of total polarization Pm vs 1/T has slope while for molecule B, it has a finite positive slope. ChCl3 and CCl4 which one could be molecule A and why

Answer 1

Solution.

$Pm = \frac{Na}{3E0}(\alpha + \frac{\mu^2}{3kT})$

For CCl4 $\mu$ = 0, so

$Pm = \frac{Na \times \alpha}{3E0}$

Pm does not depend on temperature in the case when the dipole moment is 0. Therefore, the A molecule is CCl4. The B - CHCl3 Molecule.

Answer:

Therefore, the A molecule is CCl4. The B - CHCl3 Molecule.