The mass of NaCl needed for the solution is:
"150g\\times0.075=11.3g"
Therefore, the mass of water is "150g-11.3g=138.7g".
Assuming that the density of water is equal to "0.9982g\/mL" at 20oC, the volume of water needed is "V=\\frac{138.7g}{0.99982g\/mL}=139mL"
So, in order to prepare this solution, 11.3 g of NaCl should be weighted and added to 139 mL of pure water.
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