Question

0.5M KOH is one of the reagents needed in the qualitative determination of stimulant cathartic anthraquinone in plants. How many grams of KOH are required to prepare 1L solution? MW KOH = 56 g/mol

Answer 1

$C=\frac{n}{V}$

$n=C\times V=0.5\times1=0.5$ mol

$m=n\times M=0.5\times56=28$  g