Balanced reaction:
2H2 + O2 → 2H2O
M(H2) = 2 g/mol
M(O2) = 32 g/mol
"n = \\frac{m}{M}"
n(H2) "= \\frac{19.2}{2} = 9.6 \\;mol"
n(O2) "= \\frac{40.1}{32} = 1.25 \\;mol"
Proportion from the reaction:
H2: O2 = 2:1
Proportion from the reactants masses:
H2: O2 = 9.6:1.25
O2 is the limiting reactant that will completely react.
n(H2O) = 2n(O2) "= 2\\times1.25 = 2.5\\; mol"
M(H2O) = 18 g/mol
m(H2O) "= n\\times M = 2.5\\; mol\\times 18\\;g\/mol = 45\\; g"
Answer: 45 g
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