25.0 g of an unknown metal at 90.0C is added to 50.0 g of water at 25.0 oC causing the temperature of the water rises to 29.8oC. What is the specific heat capacity and the identity of the metal?
1
Expert's answer
2012-09-14T09:34:32-0400
qmetal = qwater
By substitution, we have (metal values on the left, water values on the right):
Comments
Leave a comment