if CH3COOH=0.1mole per dm3 and that of CH3COONa=1.0 mol3 per dm3.The pH of buffer is
"CH_3COO" is a monoacidic weak acid with "Na"as an alkali metal hence "CH_3COONa"
The general expression for The weak acid "Ka" is ;
"Ka" "=" "[H^+_{aq}][A^-_{aq}] \\over [HA_{aq}]" "mol\/dm^3"
Which translates to;
"[H^+_{aq}][salt]\\over [acid]" "mol\/dm^3"
Hence "[CH_3COO^-_{aq}][Na^+_{aq}]\\over [CH_3COONa]"
The pKa value of "CH_3COONa" "=4.745"
From the formula
"pH=pKa+log" "[A^-]\\over[HA]"
"=4.745+log" "[1.0]\\over [0.1]"
"=4.745+log 10"
"=4.745+1"
"=5.745"
The pH of the buffer is "5.745"
Hence the the buffer is acidic.
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