Answer to Question #125994 in Inorganic Chemistry for Siyamthanda

Question #125994
1 Write down the Hydrolysis reaction for acetic acid (CH3COOH)
2 Write the equilibrium expression of these reaction(Ka)
3 Calculate the pH of 0.1M solution of acetic acid
1
Expert's answer
2020-07-13T07:29:43-0400

1. The hydrolysis reaction equation for the acid is;

"CH_3COOH+H_2O\\leftrightharpoons H^+_{(aq)}+CH_3COO^-_{(aq)}"

"H^+_{(aq)}+H_2O_{(l)}\\to H_3O^+_{(aq)}" .

The overall hydrolysis reaction is;

"CH_3OOH+H_2O\\leftrightharpoons CH_3COO^-_{(aq)}+H_3O^+_{(aq)}" 2. The equilibrium expression for the reaction is;

"K_a =" "{[CH_3COO^-][H_3O^+]}\\over {[CH_3COOH]}"

3. For acetic acid"pK_a=4.76" and "-log _{10} [H^+]=pH"

"4.76=log_ {10}(0.1)+2.pH"

"2.pH=4.76+1"

"2.pH= 5.76"

"pH=2.88"

The pH for "0.1 M" acetic acid"=2.88"


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