1. The hydrolysis reaction equation for the acid is;
"CH_3COOH+H_2O\\leftrightharpoons H^+_{(aq)}+CH_3COO^-_{(aq)}"
"H^+_{(aq)}+H_2O_{(l)}\\to H_3O^+_{(aq)}" .
The overall hydrolysis reaction is;
"CH_3OOH+H_2O\\leftrightharpoons CH_3COO^-_{(aq)}+H_3O^+_{(aq)}" 2. The equilibrium expression for the reaction is;
"K_a =" "{[CH_3COO^-][H_3O^+]}\\over {[CH_3COOH]}"
3. For acetic acid"pK_a=4.76" and "-log _{10} [H^+]=pH"
"4.76=log_ {10}(0.1)+2.pH"
"2.pH=4.76+1"
"2.pH= 5.76"
"pH=2.88"
The pH for "0.1 M" acetic acid"=2.88"
Comments
Leave a comment