Answer to Question #125789 in Inorganic Chemistry for Yanga

Question #125789
2Ca3(PO4)+ 6SiO2+ 10C = P4+10CO+6CaSiO3

How many grams of calcium phosphate are required to give 5g of P4
1
Expert's answer
2020-07-10T05:24:05-0400

Molar mass of "P_4" "=123.88g\/mol"

Molar mass of "Ca_3(PO_4)_2" "=310.18g\/mol"

From the balanced chemical equation;

"2" moles of "Ca_3(PO_4)_2" Produces "1" mol "P_4"

"Mole=" "Mass\\over Molar mass"

"Mass_{(g)}" "=" "Molar mass*Mole"

"5gP_4=" "1mol P_4\\over 123.88_gP_4" "*" "2mol Ca_3(PO_4)_2 \\over 1mol P_4" "*" "310.8_g Ca_3(PO_4)_2 \\over 1mol Ca_3(PO_4)_2"

"= 25.09_g Ca_3(PO_4)_2"

Mass of "Ca_3(PO_4)_2=25.09g"


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