Molar mass of "P_4" "=123.88g\/mol"
Molar mass of "Ca_3(PO_4)_2" "=310.18g\/mol"
From the balanced chemical equation;
"2" moles of "Ca_3(PO_4)_2" Produces "1" mol "P_4"
"Mole=" "Mass\\over Molar mass"
"Mass_{(g)}" "=" "Molar mass*Mole"
"5gP_4=" "1mol P_4\\over 123.88_gP_4" "*" "2mol Ca_3(PO_4)_2 \\over 1mol P_4" "*" "310.8_g Ca_3(PO_4)_2 \\over 1mol Ca_3(PO_4)_2"
"= 25.09_g Ca_3(PO_4)_2"
Mass of "Ca_3(PO_4)_2=25.09g"
Comments
Leave a comment