Question

2Ca3(PO4)+ 6SiO2+ 10C = P4+10CO+6CaSiO3

How many grams of calcium phosphate are required to give 5g of P4

Answer 1

Molar mass of $P_4$ $=123.88g/mol$

Molar mass of $Ca_3(PO_4)_2$ $=310.18g/mol$

From the balanced chemical equation;

$2$ moles of $Ca_3(PO_4)_2$ Produces $1$ mol $P_4$

$Mole=$ $Mass\over Molar mass$

$Mass_{(g)}$ $=$ $Molar mass*Mole$

$5gP_4=$ $1mol P_4\over 123.88_gP_4$ $*$ $2mol Ca_3(PO_4)_2 \over 1mol P_4$ $*$ $310.8_g Ca_3(PO_4)_2 \over 1mol Ca_3(PO_4)_2$

$= 25.09_g Ca_3(PO_4)_2$

Mass of $Ca_3(PO_4)_2=25.09g$