Answer to Question #125768 in Inorganic Chemistry for Lisakhanya

Question

Calculate the mass of ferric oxide (FeO3) that will be produced by complete oxidation of 100g of Iron

Answer 1

Solution:

2Fe+3O₂=2FeO₃

n(Fe)=m(Fe)/M(Fe)=100/56=1.786 mol.

n(FeO₃)=n(Fe)=1.786mol.

m(FeO₃)=n(FeO₃)*M(FeO₃)=1.786mol*104g/mol=185.7g.

Answer: 185.7g