How many grams of KClO3 is taken such that 5.6 litres of oxygen is liberated at NTP?
1
Expert's answer
2012-07-27T10:02:37-0400
NTP - Normal Temperature and Pressure - is defined as air at 20oC (293 K) and 1 atm ( 101.325 kPa). The KClO3 decomposition: 2 KClO3 = 2 KCl + 3 O2 The amount of oxygen is pV = nRT n(O2) = pV / RT = 1 atm * 5.6 L / (0.08206 L*atm/K*mol * 293 K) = 0.233 mol n(KClO3) = (2/3)*n(O2) = 0.233*(2/3) = 0.155 mol The mola mass of KCLO3 is M(KClO3) = 122.5 /mol The mass of KClO3 is
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment