Question

What is the mass, in mg, of carbon formed when 3.0 × 10−3 mol of propene undergoes incomplete combustion?
2C3H6 + 3O2 ⟶ 6C + 6H2O

Answer 1

Following to the reaction:

n(C)= 0,003 mol • 6 / 2 = 0,009 mol.

m(C) = n•M = 0,009 • 12 = 0,108 g = 108 mg