Atoms in "B" form ccp( cubic close parking) and is analogous to fcc( face centred cubic.
The effective number of atoms of "B" in lattice is thus;
"(" "1\\over 8" "*8)" "+(" "1\\over 2" "*6)" "=4"
Number of tetrahedral voids in "A" which forms (ccp or fcc) is "n" atoms or anions.
The number of tetrahedral voids will thus be "1\\over 2" "(2n)" "=n"
"n=4"
The compound is thus "A_4B_4"
It's simplified ration "A:B=4:4" "=1:1"
The compound has formula "AB"
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