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Answer to Question #120988 in Inorganic Chemistry for Sam

Question #120988
(2.500*10^-1) mol/L NaOH solution was used to neutralize (1.30*10^1) mL hydrochloric acid. What is the concentration of the hydrochloric acid
1
Expert's answer
2020-06-12T07:30:02-0400

13 ml hydrochloric acid = V(acid)

0.25 M NaOH = C

Cacid-?

Cacid= (C(NaOH)*V(NaOH))/(V(acid))


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