Question #120988

(2.500*10^-1) mol/L NaOH solution was used to neutralize (1.30*10^1) mL hydrochloric acid. What is the concentration of the hydrochloric acid

Expert's answer

13 ml hydrochloric acid = V(acid)

0.25 M NaOH = C

Cacid-?

Cacid= (C(NaOH)*V(NaOH))/(V(acid))


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Place free inquiry
Calculate the price
Learn more about our help with Assignments: Inorganic Chemistry
Our fields of expertise
Submit Your Assignment. We Can Do It.
LATEST TUTORIALS
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Canada #339914 on Dec 2023