Question

(2.500*10^-1) mol/L NaOH solution was used to neutralize (1.30*10^1) mL hydrochloric acid. What is the concentration of the hydrochloric acid

Answer 1

13 ml hydrochloric acid = V(acid)

0.25 M NaOH = C

C_acid-?

C_acid= (C(NaOH)*V(NaOH))/(V(acid))