Question

A 6.20mL sample of 0.10mol/hydrochloride acid is used to standardized sodium hydroxide. What the concentration of the sodium hydroxide?

Answer 1

The reaction between hydrochloric acid and sodium hydroxide is as following:

$NaOH + HCl \rightarrow NaCl + H_{2}O;$

Thus, we can calculate the amount in moles of HCl in a given solution:

$n(HCl)=C(HCl)*V(HCl)=0.10mol/L*0.00620L=6.2*10^{-4}mol;$

The reactants are interacting in a ratio 1 to 1. Thus, the amount of sodium hydroxide is equal to 6.2*10^-4 moles.