WB = unknown
MB = 53.5 g/mol
WA = 0.05 kg
∆T = 5 °C
Kf = 1.86 °C×kg/mol
∆T = (Kf×WB)/(MB×WA)
WB = (∆T×MB×WA)/Kf
WB = (5×53.5×0.05)/1.86 = 7.19 g
Answer: 7.2 g
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