WB - ?; MB = 53.5 g/mol; WA = 0.05 kg; ∆T = 5 °C
∆T = (Kf×WB)/(MB×WA)
WB = (∆T×MB×WA)/Kf
WB = (5 °C × 53.5 g/mol × 0.05 kg)/(1.86 °C kg/mol) = 7.19 g
Answer: 7.19 g