By definition, 1.45 = [B]octanol / [B]water
number of moles B = 3.5/101.19 = 0.0346 moles
[B]octanol = (0.0346 - x)/0.100
[B]water = x/0.050
where x is number of moles B in water.
1.45 = (0.0346 - x)*0.050/0.100x = (0.0346 - x)/2x
x = 0.0089 moles B in water
mass = 0.0089*101.19 = 0.898 g B in water
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