Answer to Question #119778 in Inorganic Chemistry for A

Question

The rate constant of a chemical reaction increased from 0.100 s−1 to 3.00 s−1 upon raising the temperature from 25.0 ∘C to 37.0 ∘C .May I please ask what is the activation energy of the reaction?Thanks

Answer 1

T₁=25+273=298 K

T₂= 37+273=310 K

E_a=2.303*RT₁T₂*lg(k2/k1)/(T₂-T₁)=2.303*8.314*298*310*1.477/12=217711.4 J/mol=2.18*10^2 kJ/mol