Question

To neutralize 25 cm3 of 0,20 M KOH you need: a) 25 cm3 of 0,40 M hydrochloric acid b) 20 cm3 of 0,25 M hydrochloric acid c) 50 cm3 of 0,10 M hydrochloric acid d) 25 cm3 of 0,10 M hydrochloric acid e) none

Answer 1

To neutralize 25 cm3 of 0,20 M KOH you need 0.025L*0.20mol/L=0.005mol of an acid.

This amount of acid is contained in the solution of variants B and C.

The answer: B and C.