Answer to Question #117704 in Inorganic Chemistry for kenneisha

Question

At 500k, Kc= 0.061 for the reaction N2 (g)+ 3H2(g)⇌ 2NH3(g). If analysis of the reaction vessel at 500K shows that the composition is 3.00mol/L N2, 2.00mol/LH2 and 0.500mol/L NH3. In which direction does the reaction proceed and why?

Answer 1

Answer:

Q_c = 0.010

K_c=0.061

Q_c<K_c then the reaction will shift right to reach equilibrium.

Explanation:

Step 1:

Data given:

Temperature = 500 °C

K_c=0.061

3.00mol/L N₂

2.00mol/L H₂

0.50mol/L NH₃

Step 2:

Calculate Q

Q=[products]/[reactants]=[NH3]²/ [N2][H2]³

If Qc=Kc then the reaction is at equilibrium. 

If Qc<Kc then the reaction will shift right to reach equilibrium.

If Qc>Kc then the reaction will shift left to reach equilibrium. 

Q = (0.50)² / (3.00 * 2.00³)

Q = 0.25/24

Q = 0.010