Answer to Question #113182 in Inorganic Chemistry for Blessing

Question

When 0.25 L of liquid nitrogen (d = 0.807 g/mL) is vaporized, what volume does the resulting gas occupy at 25 °C and 5.00 atm

Answer 1

Solution.

$p \times V= \frac{m}{M}\times R\times T$

$V = \frac{m \times R \times T}{p \times M}$

$V = \frac{250 \times 0.807 \times 8.31 \times 298}{28 \times 506625} = 0.03 \ ml$

Answer:

V = 0.03 ml