Answer to Question #111525 in Inorganic Chemistry for Jonathan

Question

How many grams of nitric acid can be prepared from the reaction of 138 grams of NO2 with 54 grams of H2O according to the equation: 3NO2 + H2O -> 2HNO3 + NO

Answer 1

n(NO2) = 138/46 = 3 mol

n(H2O) = 54/18 = 3 mol

water in excess, therefore:

n(HNO3) = n(NO2)*2/3 = 2 mol

m(HNO3) = 2*63 = 126 g