Question #107600

If 3.15g of mercury oxide are thermally decomposed to mercury and oxygen
(a) What mass of mercury will be produced?
(b) How many oxygen molecules will be produced?

Expert's answer

2HgO=2Hg+O22HgO = 2Hg + O_2

n(HgO)=n(Hg)=0.5n(O2)n(HgO) = n(Hg) = 0.5n(O_2)

n(HgO)=mM=3.15216.59=0.0145moln(HgO) = {m \over M} = {3.15 \over 216.59} = 0.0145mol

m(Hg)=nM=0.0145200.59=2.91gm(Hg) = nM = 0.0145*200.59 = 2.91 g

N(O2)=0.5nNA=0.50.01456.021023=4.36451021N(O_2) = 0.5nN_A = 0.5*0.0145*6.02*10^{23} = 4.3645*10^{21}

Answer: (a) 2.91g; (b) 4.3645*1021.


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