Answer to Question #106427 in Inorganic Chemistry for Andrew

Question

For the synthesis of butylethanoate 11x10^-3 mol of the alcohol and 13x10^-3 mol of carboxylic acid were used. Assuming that you obtained 6.6x10^-3 mol of butylethanoate, calculate the percentage yield.

Answer 1

find the amount of substance theoretical product

count on alcohol, it reacted less

 11x10^-3:1=х:1,

х=11x10^-3.

calculate the percentage yield.

$v=\frac{vp}{vt}=\frac{6.6\times10^-3}{11\times10^-3}=0.6$

$0.6\times100=60$ , 60%