Question

How many molecules (not moles) of NH3 are produced from 8.45×10−4 g of H2?

Answer 1

Solution.

$N2 + 3H2 = 2NH3$

$n(H2) = \frac{8.45 \times 10^{-4}}{2} = 4.23 \times 10^{-4} \ mol$

$n(NH3) = \frac{4.23 \times 10^{-4} \times 2}{3} = 2.82 \times 10^{-4} \ mol$

$N(NH3) = n(NH3) \times Na = 2.82 \times 10^{-4} \times 6.02 \times 10^{23} = 1.7 \times 10^{20} \ molecules$

Answer:

$N(NH3) = 1.7 \times 10^{20} \ molecules$