Answer to Question #99891 in General Chemistry for Beverlie

Question

A gaseous mixture consists of 1.27 mol of helium, 0.36 mol of neon, and 1.58 mol of argon.
What is the mole fraction of helium in the mixture?

Answer 1

æ - mole fraction, n -number of molesæ_components=n_components / $\sum$ n_{all components} $\sum$ æ_components=1æ_He=n_He/n_Ne+n_He +n_Aræ_He=0,395