Initial conditions : Vi=3.1L;ni=5.51molV_i=3.1L;n_i=5.51molVi=3.1L;ni=5.51mol
Final conditions : Vf=18.1L;nf=?V_f=18.1 L; n_f=?Vf=18.1L;nf=?
As pressure and temperature remain constant;
Vi/Vf=ni/nfV_i/V_f=n_i/n_fVi/Vf=ni/nf
⟹ nf=Vfni/Vi\implies n_f=V_fn_i/V_i⟹nf=Vfni/Vi
=18.1∗5.51/3.1=18.1*5.51/3.1=18.1∗5.51/3.1
=32.17mol=32.17 mol=32.17mol (Answer)
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments