Answer to Question #99698 in General Chemistry for Levi

Question

Titration data is:
0.190 M NaOH (titrant)
Volume of H2SO4 (analyte) is 10 mL, Initial Burette Reading is 27.40 mL, final burette reading is 36.20 mL thus the total volume of NaOH added is 8.80 mL. Calculate molarity of H2SO4 (mol/L).

Answer 1

$M_1=0.19M(NaOH)$

$V_1=8.80 ml(NaOH)$

$V_2=10ml(H_2SO_4)$

$n_1=1(NaOH);n_2=2(H_2SO_4)$

$n_1M_1V_1=n_2M_2V_2$

$M_2=n_1M_1V_1/n_2V_2$

$M_2=(1.0.19.8.80)/(2.10)=0.0836M(Answer)$