Solution.
1.
Find the standard enthalpy of formation of Cu from CuO.
ΔH=(ΔH(Cu)+ΔH(CO2))−(ΔH(CuO)+ΔH(CO))
ΔH=(0+(−393.51))−(−155.00+(−110.52))=−127.99 molkJ
Find the standard enthalpy of cu formation from CuO for 1.37 cu moles.
ΔH=1.37×(−127.99)=−175.35molkJ
2.
The energy for processing copper is found by the formula:
ΔH=ΔH0+∫ΔCpΔT
ΔH=13.0+24.5×(1084.5−25)=38.96molkJ
Answer:
ΔH=−175.35molkJ
ΔH=38.96molkJ
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