Solution.
1.
Find the standard enthalpy of formation of Cu from CuO.
"\\Delta H = (\\Delta H (Cu) + \\Delta H (CO2)) - (\\Delta H (CuO) + \\Delta H (CO))"
"\\Delta H = (0 + (-393.51)) - (-155.00 + (-110.52)) = -127.99 \\ \\frac{kJ}{mol}"
Find the standard enthalpy of cu formation from CuO for 1.37 cu moles.
"\\Delta H = 1.37 \\times (-127.99) = - 175.35 \\frac{kJ}{mol}"
2.
The energy for processing copper is found by the formula:
"\\Delta H = \\Delta H0 + \\int \\Delta Cp \\Delta T"
"\\Delta H = 13.0 + 24.5 \\times (1084.5-25) = 38.96\\frac{kJ}{mol}"
Answer:
"\\Delta H = - 175.35 \\frac{kJ}{mol}"
"\\Delta H = 38.96 \\frac{kJ}{mol}"
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