The balanced chemical equation is "2NaOH+H_2SO_4\\to Na_2SO_4+H_2O"
As there are equal concentrations of "H^+" and "OH^-" present in the solution so there will be no "NaOH" and "H_2SO_4" left in the container.
Mass of "H_2SO_4" treated in the container"=53.6\\times10^{-3}\\times98=5.2528g"
Enthalpy change"=mC_p\\Delta T=189.925J"
Hence, enthalpy change per mole"=\\frac{189.925}{53.6\\times10^{-3}}=3543.38601\\frac{J}{mol}"
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How did you get 189.25J
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