Question #99585

A 107.2 mL sample of 1.00 M NaOH is mixed with 53.6 mL of 1.00 M H2SO4 in a large Styrofoam coffee cup; the cup is fitted with a lid through which passes a calibrated thermometer. The temperature of each solution before mixing is 22.05 °C. After adding the NaOH solution to the coffee cup and stirring the mixed solutions with the thermometer, the maximum temperature measured is 30.70 °C. Assume that the density of the mixed solutions is 1.00 g/mL, that the specific heat of the mixed solutions is 4.18 J/(g·°C), and that no heat is lost to the surroundings.
1. Write a balanced chemical equation for the reaction that takes place in the Styrofoam cup. Remember to include phases in the balanced chemical equation.
2. Is any NaOH or H2SO4 left in the Styrofoam cup when the reaction is over?
3. Calculate the enthalpy change per mole of H2SO4 in the reaction. answer must be in kj/mol

Expert's answer

The balanced chemical equation is 2NaOH+H2SO4Na2SO4+H2O2NaOH+H_2SO_4\to Na_2SO_4+H_2O

As there are equal concentrations of H+H^+ and OHOH^- present in the solution so there will be no NaOHNaOH and H2SO4H_2SO_4 left in the container.

Mass of H2SO4H_2SO_4 treated in the container=53.6×103×98=5.2528g=53.6\times10^{-3}\times98=5.2528g

Enthalpy change=mCpΔT=189.925J=mC_p\Delta T=189.925J

Hence, enthalpy change per mole=189.92553.6×103=3543.38601Jmol=\frac{189.925}{53.6\times10^{-3}}=3543.38601\frac{J}{mol}


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