Answer to Question #99537 in General Chemistry for MIGUEL GONZALEZ

Question

A sample of 52g of neon is placed in a balloon with volume 10.3L at 25 °c. If 34.8 g of neon is added at constant temp and pressure, what's the new volume of the balloon

Answer 1

Mol Wt. Of Ne = 20 g/mol

52g = 2.6 mol (n)

Volume, V = 10.3L

T= 298K

Pressure,P = nRT/V

= (2.6*.082*298)/10.3

=6.2 atm pr

After addimg 34.8g of Ne the mole no will be =86.8/20

= 4.34 mole

New Volume = (4.34*.082*298)/6.2

= 17.1 Liter