Solution.
a.
2MnO4−+5SO2+2H2O=5SO42−+2Mn2++4H+2MnO4^- + 5SO2 + 2H2O = 5SO4^{2-} + 2Mn^{2+} + 4H^+2MnO4−+5SO2+2H2O=5SO42−+2Mn2++4H+
b.
2MnO4−+5SO2+4OH−=5SO42−+2Mn2++2H2O2MnO4^- + 5SO2 + 4OH^- = 5SO4^{2-} + 2Mn^{2+} + 2H2O2MnO4−+5SO2+4OH−=5SO42−+2Mn2++2H2O
Answer:
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