ΔG° = - R.T.ln(K)
= - 8.3145 J∙K⁻¹∙mol⁻¹ ∙ (427 + 273) K ∙ ln(9.4×10⁻⁵)
= 5.397×10⁴ J∙mol⁻¹
= 53.97 kJ∙mol⁻¹
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