Question

The equilibrium constant at 427°C for the reaction N2(g) + 3H2(g) ⇆ 2NH3(g) is Kp = 9.4 x 10-5. Calculate the value of G° for the reaction at this temperature.

Answer 1

ΔG° = - R.T.ln(K)

= - 8.3145 J∙K⁻¹∙mol⁻¹ ∙ (427 + 273) K ∙ ln(9.4×10⁻⁵)

= 5.397×10⁴ J∙mol⁻¹

= 53.97 kJ∙mol⁻¹