Solution.
ΔH=Σ(ΔH(broken bonds))−Σ(ΔH(formed bonds))
1.
Divide the coefficients in the reaction equation:
CO+NO=CO2+2N2
ΔH=1072+628−(799×2)−21×941=−368.5 kJ/mol
2.
This equation can be left the same.
ΔH=436+151−(2×299)=−11 kJ/mol
Answer:
1.
ΔH=−368.5 kJ/mol
2.
ΔH=−11 kJ/mol
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