Question

A sample of gold was heated from 25.0⁰C to 45.3⁰C. In the process, 267.1 J of heat were absorbed. What mass of gold was in the sample? (The specific heat of gold is 0.129 J/g.⁰C)

Answer 1

Q98353

Solution:

Given, $Q=267.1J;s_{gold}=0.129J/g⁰C$

$T_i =25.0⁰C;T_f=45.3⁰C$

$\implies \Delta T =45.3-25=18.3⁰C$

$Q=ms\Delta T$

$\implies m=Q/(s\Delta T)$

$=267.1/(0.129*18.3)$

$=113.144gms.$ (Answer)

Thus, mass of gold in the sample is $113.144gms.$