Answer to Question #98353 in General Chemistry for Mario

Question #98353
A sample of gold was heated from 25.0⁰C to 45.3⁰C. In the process, 267.1 J of heat were absorbed. What mass of gold was in the sample? (The specific heat of gold is 0.129 J/g.⁰C)
1
Expert's answer
2019-11-11T07:47:37-0500

Q98353


Solution:

Given, "Q=267.1J;s_{gold}=0.129J\/g\u2070C"

"T_i =25.0\u2070C;T_f=45.3\u2070C"

"\\implies \\Delta T =45.3-25=18.3\u2070C"


"Q=ms\\Delta T"

"\\implies m=Q\/(s\\Delta T)"

"=267.1\/(0.129*18.3)"

"=113.144gms." (Answer)


Thus, mass of gold in the sample is "113.144gms."



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