Question #98352
How much heat is needed to warm 325 g of water from 25⁰C to 92.5⁰C ? (knowing that the specific heat of water is 4.18J/g.⁰C)
1
Expert's answer
2019-11-11T07:47:40-0500

Q=m×C×changeintemperatureQ=m×C×change in temperature

Q=325g×4.18J/g.°C×(92.525.0)Q=325g×4.18J/g.°C×(92.5-25.0)

Q=91.699KJQ=91.699KJ (Answer)







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