Question #98227
A sample of N2 gas occupiea 9.20 L at 21 degrees C and 0.959 atm. If the pressure is tuned to 1.15 atm at constant temperature what is the newly occupied volume
1
Expert's answer
2019-11-11T07:48:39-0500

Q98227


Soluton :

Given; Vi=9.20LV_i=9.20L ;Ti=Tf=294K;Pi=0.959atm;Pf=1.15atm;T_i=T_f=294K; P_i=0.959atm; P_f=1.15atm

To find: VfV_f


As number of moles stays constant;

PV=nRT    PV/T=constantPV=nRT \implies PV/T=constant

PiVi/Ti=PfVf/Tf\therefore P_iV_i/T_i=P_fV_f/T_f

    Vf=(PiViTf)/(TiPf)\implies V_f=(P_iV_iT_f)/(T_iP_f)

=(0.9599.2294)/(2941.15)=(0.959*9.2*294)/(294*1.15)

=7.672L=7.672L (Answer)


Thus, newly occupied volume of N2N_2 gas sample is 7.672L7.672L


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