I am sorry, I made a typo in previous answer, this is the right version!
1) 1.535 g of X -> 1.365 g of Cu
1.535 – 1.365 = 0.170g of O
Aw of Cu =63.5, of O = 16
For Cu 1.365 g / 63.5 = 0.02 mol
For O 0.170 g / 16 = 0.01 mol
X = Cu2O
There is missing information about mass of Y yielded of copper, which is necessary for solving this task, so I tried to find the full question and I will be giving answer according to the founded missing part.
Copper reacts with oxygen to form two oxides X and Y on analysis, 1.535g of X yielded 1.365g if copper and 1.450g of Y yield 1.160g of copper. Determine the chemical formula of X and Y and calculate the mass of copper which can react with 0.500g of oxygen to yield X and Y?
2) 1.450 g of Y -> 1.160 g of Cu
1.450 – 1.160 = 0.290 g of O
For Cu = 1.160 g / 63.5 = 0.018 mol
For O = 0.290 g / 16 = 0.018 mol
Y = CuO
3) total mass of O = 0,170 g + 0,290 g = 0.460 g
Total mass of Cu = 1.160 g + 1. 365 g = 2.525 g
0.460 g of O -> 2.525 g of Cu
0.500 g of O -> (2.525 x 0.5) / 0.460 = 2.745 g of Cu
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