V=0.350L
∆m=82.786g-82.561g=0.225g the mass of an added gas
P=733mmHg/760=0.964atm
T=22°C+273.15=295K
Rearrange the ideal gas law to solve for n:
PV=nRT
n=PV/(RT)=(0.964atm*0.350L)/(0.08206atm*L/(mol*K)*295K)=0.0139mol
Find the ratio of the mass to the number of moles of an unknown gas to find its molar mass: 0.225g/0.0139mol=16.1g/mol
The molar mass of Ar is 39.95 g/mol, of NO is 30.01 g/mol, and of CH4 is 16.04 g/mol
Thus, the gas in the bulb is methane(CH4)
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