Answer to Question #97972 in General Chemistry for ian martin

Question #97972

CH₄ + 2 O₂ → CO₂ + 2 H₂O How many grams of water are made from the combustion of 4.05 x 10²² molecules of methane with excess oxygen?

Expert's answer

4.05 x 10 ^22 / 6.02 x 10^23= 0.0672757475 mol.

2 x 0.0672757475 x 18= 2.42192691 g of water.

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