Let 100 gm of compound is taken
Then
Moles of Ca taken = "\\frac{25.9}{40}=0.6475"
Moles of S taken = "0.65"
Moles of oxygen taken = "\\frac{}{}" "\\frac{41.6}{16}=2.6"
Moles of water = "\\frac{11.7}{18}=0.65"
Dividing all term by 0.65 for getting simple whole no. Ratio
We get,
Ratio of Ca : S : O : "H_2O" = 1 : 1 : 4 : 1
So the compound is
"CaSO_4\u2022H_2O"
IUPAC name = Calcium sulfate
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