Question #97874

A hydrated compound contains 25.9% calcium, 20.8% sulphur,41.6% oxygen and the rest is water of crystalization. Determine the empirical formula and give its IUPAC name

Expert's answer

Let 100 gm of compound is taken

Then

Moles of Ca taken = 25.940=0.6475\frac{25.9}{40}=0.6475

Moles of S taken = 0.650.65

Moles of oxygen taken = \frac{}{} 41.616=2.6\frac{41.6}{16}=2.6

Moles of water = 11.718=0.65\frac{11.7}{18}=0.65

Dividing all term by 0.65 for getting simple whole no. Ratio

We get,

Ratio of Ca : S : O : H2OH_2O = 1 : 1 : 4 : 1

So the compound is

CaSO4H2OCaSO_4•H_2O

IUPAC name = Calcium sulfate


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