(1)
Heat taken by water = heat released by metal
So,
"75\\times4.186\\times 1.6=56.6\\times c_m\\times 68.4\\\\or\\\\c_m=0.13\\ J\\ gm^{-1}\\ K^{-1}"
Molar heat capacity = molar mass "\\times\\ c_m=26.73\\ J\\ mol^{-1}\\ K^{-1}"
(2)
Total energy required = "m_ic_i(0-(-15))+(m_i\\times334)+m_wc_w(70-0)"
"m_i=m_w=12.1\\ g\\\\c_i=2.06\\\\c_w=4.18"
"E=(12.1\\times2.06\\times15)+(12.1\\times334)+(12.1\\times4.18\\times70)\\\\\\ \\ \\ \\ =7955.75\\ J"
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