pH=pKa+lg(([NaAc]-x)/([HAc]+x))
4.8=4.76+lg((0.1-x)/(0.01+x))
lg((0.1-x)/(0.01+x))=0.04
(0.1-x)/(0.01+x)=1.096478
x=0.0425
V=1000*x/C=1000*0.425/10=4.25 (ml)
Answer: 4.25 ml.
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