To determine empirical formula,first divide the percentage of elements by their molar mass to find their relative number of moles
Relative number of moles of "C=\\frac{42.86}{12}=3.57167"
Relative number of moles of "H=\\frac{2.4}{1}=2.4"
Relative number of moles of "N=\\frac{5.88}{14}=0.42"
Relative number of moles of "Na=\\frac{9.65}{23}=0.41956\\approx0.42"
Relative number of moles of "O=\\frac{25.75}{16}=1.60"
Relative number of moles of "S=\\frac{13.46}{32}=0.42"
Then divide the relative number of moles by the smallest one.
For "C\\equiv \\frac{3.57167}{0.42}=8.5"
For "H\\equiv \\frac{2.4}{0.42}=5.71"
For "N\\equiv \\frac{0.42}{0.42}=1"
For "Na\\equiv \\frac{0.42}{0.42}=1"
For "O\\equiv \\frac{1.60}{0.42}=3.81"
For "S\\equiv \\frac{0.42}{0.42}=1"
The equivalent ratio is
"C:H:O:Na:S:N\\equiv"
"8.5:5.7:3.8:1:1:1\\equiv"
"1.9(4.5:3:2):1:1:1\\approx"
"2(4.5:3:2):1:1:1\\equiv"
"9:6:4:1:1:1"
Hence the empirical formula will be "C_9H_6O_4NaSN"
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