"HClO_4 + NaOH \u2192 NaClO_4 + H_2O"
By using Molarity equation,
"M_1V_1=M_2V_2" (1 for Acid,2 for NaOH)
Let "x" be mole fraction of "HClO_4" in the solution.
Molar mass of perchloric acid"=100.5\\ gm"
So,"\\frac{11.1}{100.5}\\times x=29.9\\times 10^{-3}\\times 0.534"
"x=0.144563"
Mass percentage"=x\\times 100=14.46" %
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