"T_1=25\\degree C;T_2=42\\degree C;m=1000\\times 5.5 \\times 10^{-3}=" "5.5 \\ kg"
"C" for water"=4.184 \\times 10^3 J\/Kg"
Energy required to raise this temperature"=" "mC(T_2-T_1)=5.5\\times 4.184 \\times 10^3\\times (42-25)=" "391.204\\times 10^3 J"
Power given"=255 J\/sec"
Time required"=\\frac{Energy}{Power}=\\frac{391.204\\times 10^3}{255}=" "154.133 \\ sec=\\frac{154.133}{60}=2.585 \\ min"
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