Answer to Question #96586 in General Chemistry for Ashley Ramos

Question

If there are 2.38 x 1023 hydrogen atoms available, how many grams of dinitrogen tetrahydride could be made?

Answer 1

Molecular weight of N2H4 is = 32 gm/mole

In 1 mole of N2H4 there are 4*6.023*10²³ atoms of H is present.

2.38*1023 hydrogen atoms =(2.38*1023)/(4*6.023*10²³) moles of N2H4

=101.6*10²³ moles of N2H4

Therefore 101.6*10²³ moles = 32*101.6*10²³ gm of N2H4 can be formed